Dr. Kevin G. TeBeest
- If a computer takes 3 seconds to invert a 60 x 60 matrix, estimate how long will it take to invert a matrix of order 300?
Answer: About 31.25 minutes
- Suppose A is square. Answer True or False: If A has a zero in its diagonal, then A is singular.
- Suppose we've used Gauss elimination to transform A into upper triangular form U.
Answer True or False: If U has a zero in its diagonal, then A is singular.
- Answer True or False: If A is singular, then using Gauss elimination to solve system Ax = b will result in dividing by 0.
- Using Gauss elimination to solve system Ax = b will produce large truncation error when WHAT is true about A?
- Using the inverse method is a
way to solve a system Ax = b.
- very efficient
- very inefficient
- Given matrix A :
A = 4 –19 –7 33
- Find A1 using the method covered in class.
- Then show that AA–1 = I and that A–1A = I .
- What is det(A) ?
- What is det(A–1) ?
Fall 2024 Students: Do Not work the problems below.- Use the inverse method to solve the system
4 –19 –7 33
x1 x2 =
12 –5 Use Gauss elimination or Maple to check your answer.
- See this Maple example for inverting a matrix.
You may then use Maple to check your answers to problems 1 and 2.
- Use Maple (as above) to obtain the inverse of coefficient matrix A:
Now use the inverse method to solve system
1 1 0 A = 1 0 1 6 2 3
1 1 0 1 0 1 6 2 3
x1 x2 x3 =
2 4 3
Do the following using an appropriate theorem covered in class (to be covered Thursday).
- Without finding the inverse of A, calculate det(A-1) for A.
A = 8 6 4 9
Prove the theorem that if A is invertible, then its inverse is unique.
Hint: Suppose B and C are both inverses of A. Show that B = C.
Warning: don't refer to either B or C as A–1. By doing so you are unknowingly assuming what you are trying to prove.
- If det(A) = 100,000 and A has order 12, what is det(¾A)? (the number is three-fourths)
Answer: 3,167.6352
- If | A | = 12,345 and A has order 8, what is | 4A–1| ?
Answer: 5.3087
- Suppose both A and B are order n and invertible. Answer the following with True or False:
- A1 = 1÷A
- (A1)1 = A
- det(A) = det(A1)
- det(A + B) = det(A) + det(B)
- (A + B)1 = A1 + B1
- (AB)1 = A1 B1
- (A + B)T   = AT + BT
- | AT |   = | A |